function F$=$turbfriction$($x$)$

$\%$x$(1)=$diameter

$\%$x$(2)=$velocity

$\%$x$(3)=$Reynolds Number

$\%$x$(4)=$friction

F$=[$x$(2)-0\mathrm{.}35/(3\mathrm{.}14*$x$(1)*$x$(1)/4)$;

x$(3)-$x$(2)*$x$(1)/(1\mathrm{.}655*10^(-5))$;

$1/$sqrt$($x$(4))+2\mathrm{.}0*$log$10(2\mathrm{.}51/($x$(3)*$sqrt$($x$(4))))$;

x$(4)-20*$x$(1)*2*9\mathrm{.}81/(150*$x$(2)*$x$(2))]$;function F$=$turbfriction$($x$)$

options$=$optimset$(\text{'}$tolx$\text{'},1$e$-18,$'maxfunevals',$4000000,$'tolfun',$1$e$-18,$'maxiter',$200000)$

$[$x$,$fval$]=$ fsolve$(\text{'}$turbfriction$\text{'},[0\mathrm{.}10\mathrm{.}11000000\mathrm{.}1],$options$)$

can you calculate the diameter with using octave for assigned conditions for methanol? and please use codes and results screenshots?

$\backslash$table$[[\backslash$table$[[$Methanol$],[($liquid$)]],10,30,803\mathrm{.}0,6\mathrm{.}953\backslash$times $10^(-4)]]$