Function Name: MathWorks

Inputs:

1. ( double ) 1XM vector of your scores

2. ( double ) 1XN vector of your friend's scores

3. ( double ) 1XK vector of your second friend's scores

Outputs:

1. ( double ) 1X3 vector of score statistics

Topics: ( mean/median/mode ), ( sorting )

Banned Functions:

mean, median

Background:

There is only ONE correct way to do math. Luckily, the world's greatest

comedian, Tom Middleditch, can teach you how to perfect the art of math. A-boopity-boop-boop!

Function Description:

You and two friends are in a math competition, and receive scores from various judges. Your

scores are represented by the values in the first input vector. Your first friend's scores are

represented by the values in the second input vector. Your second friend's scores are

represented by the values in the third input vector.

Find the average of your scores (rounded to one decimal place), the median of your first

friend's scores, and the mode of your second friend's scores. The mean() and median()

functions are banned, so you will have to figure out how to calculate these values without the

aid of those functions. Finally, combine these three values into one vector, and sort this vector

in descending order.

Example:

myScores = [10, 9, 10]

friend1 = [1, 0, 10000, 0, -1]

friend2 = [1, 2, 1, 1000]

scoreStats = MathWorks(myScores, friend1, friend2)

scoreStats [9.7, 1, 0]

Notes:

The length of the second input is guaranteed to be odd

One value is guaranteed to appear more than the others in the third input

Please solve without using conditional statements and iterations!!!! Also do not use the median function. Please help me get the median of the vector input without using the inbuilt median function!!!!