\fWhat is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? 8 h m R, Submit Hint I give up! Feedback: deduction per feedback. er hint. Hints remaining: 4 If the current through the middle part of the loop 1s 7} = 4.75 amps, what is the current through the top loop, /5, in amps