. f(x) is continuous on [ - 2, 4] O -9 is not between -2 and 4 so the IVT does not apply f(x) is continuous on [ - 2, 4] -9 is between f( - 2) = 24 and f(4) = - 24 C = 1, C=9 Let f(x) =x2 - 10x on [ - 2, 4] . Use the IVT to determine if there is a solution to f(x) = - 9 in the interval between -2 and 4. If so, find the value of c in the interval such Find the inflection point(s) for the function f(x) = - 2x6 +3x5+12x -2. that f(c) = - 9 f(x) is continuous on [ - 2, 4] O (0, -2) and (1, 11) O -9 is between f( - 2) = 24 and f(4) = - 24 C=9 O (0,0) and (1,0) f(x) is continuous on [ - 2, 4] O (0, 12) and (1, 15) O -9 is between f( - 2) = 24 and f(4) = - 24 C = 1 11. O (-1, -19) and (0, - 2) Find the following indefinite integral: Consider the function f(x) = -8x+1 ifx