Question: f(x)= using newton-raphson method find root,x=1 x=1 tol=0.1 derivative f(x)= I tried to write code in c++ #include #include using namespace std; double f(double x)
f(x)=
using newton-raphson method find root,x=1 x=1 tol=0.1
derivative f(x)=
I tried to write code in c++
#include
int main () { double x=1*M_PI/180.0; double err; double tol=0.01; while (1) { err=f(x)/f1(x); x=x-err; cout * tant - 1 tanx +(1+tan-I) *I
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