Question: f=x*exp(x)-1 and g=diff(f) , so f = ,why epson = 5* 10^-(n+1) what are both vpa() and sub() doing?

f=x*exp(x)-1 and g=diff(f) , so f = f=x*exp(x)-1 and g=diff(f) , so f = ,why epson = 5* 10^-(n+1) ,why epson = 5* 10^-(n+1)

what are both vpa() and sub() doing?

what are both vpa() and sub() doing?

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