Question: g ( x ) = { x - 1 , x - 1 6 x - 2 , - 1 = 3 a . Where

g(x)={x-1,x-16x-2,-1=3
a. Where is g(x) discontinuous? Explain using limits!
g ( x ) = { x - 1 , x - 1 6 x - 2 , - 1 = 3 a .

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