genetics help

For questions 3 and 4, write your null hypothesis, perform a chi-square analysis, and answer the questions. 3) Null Hypothesis: Class Data Observed Expected O - E (0 - E)2 (0 -E)2/E Green 315 Polka-dot 85 Degrees of freedom = X2 = p = Fail to Reject or Reject null hypothesis? 4) Null Hypothesis: Data Observed Expected | O - E (0 - E)2 (0 -E) 2/E Round Yellow 910 Round Greer 290 Wrinkled Yellow 320 Wrinkled Green 80 Degrees of freedom = X2 = p = Fail to Reject or Reject null hypothesis? Table 5-2 Critical Values of the X 2 Distribution af p 0.995 0.975 0.9 0.5 0.1 0.05 0.025 0.01 0.005 df TAWNY GOONO LAWN- .000 .000 0.016 0.455 2.706 3.841 5.024 6.635 7.879 0.010 0.051 0.211 1.386 4.605 5.991 7.378 9.210 10.597 0.072 0.216 0.584 2.366 6.251 7.815 9.348 11.345 12.838 0.207 0.484 1.064 3.357 7.779 9.488 11.143 13.277 14.860 AWN - 0.412 0.831 1.610 4.351 9.236 11.070 12.832 15.086 16.750 5 0.676 0.989 1.237 2.204 5.348 10.645 5 12.592 14.449 16.812 18.548 6 1.690 2.833 6.346 12.017 14.067 16.013 18.475 20.278 7 1.344 2.180 3.490 7.344 13.362 15.507 17.535 20.090 21.955 1.735 2.700 4.168 8.343 14.684 16.919 19.023 21.666 23.589 9 2.156 3.247 4.865 9.342 15.987 18.307 20.483 23.209 25.188 10 2.603 7 11 3.074 3.816 5.578 10.341 17.275 19.675 21.920 24.725 6 23.337 26.217 28.300 12 3.565 4.404 5.009 6.304 11.340 18.549 21.026 5.629 7.042 12.340 19.812 2 2 22.362 24.736 27.688 29.819 13 4.075 4.601 6.262 7.790 13.339 21.064 4 23.685 26.119 29.141 31.319 14 8.547 14.339 22.307 24.996 27.488 30.578 32.801 15