Question: Give a 99.8% confidence interval, for M1 - /2 given the following information. n1 = 30, x1 = 2.15, $1 = 0.55 12 = 20,


Give a 99.8% confidence interval, for M1 - /2 given the following information. n1 = 30, x1 = 2.15, $1 = 0.55 12 = 20, 2 = 2.19, $2 = 0.76 For degrees of freedom, use the smaller of (n1 - 1) and (n2 - 1) 2 ta = tinv(a, df) SE = sqrt(($1) ^2 / n1 + ($2)^2 / n2) E = ta * SE CI = (201 - 202)+ E Rounded both solutions to 2 decimal places
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