Give the following problem a try. If you get stuck, here is one way to work it: Essential Solution Video.

A $27mm$ thick steel plate will be used as an axial member to support a dead load of $290kN$ and a live load of $390kN.$ The yield

strength of the steel is $260$MPa.

$($a$)$ Use the ASD method to determine the minimum plate width $b$ required for the axial member if a factor of safety of $2\mathrm{.}2$ with respect

to yielding is required.

$($b$)$ Use the LRFD method to determine the minimum plate width $b$ required for the axial member based on yielding of the gross section

using the LRFD method. Use a resistance factor of ${}_t=0\mathrm{.}9$ and load factors of $1\mathrm{.}3$ and $1\mathrm{.}7$ for the dead and live loads, respectively.

$($a$)b_{\text{m}\text{i}\text{n}\text{,}\text{A}\text{S}\text{D}}=$

$mm$

$($b$)b_{\text{m}\text{i}\text{n}\text{,}LRFD}=$

$mm$