Question: Given: 4Cr (s) + 3 02 (9) - --> 2 Cr203 (aq) The substace being oxidized and the one being reduced, respectively are: O 02

Given: 4Cr (s) + 3 02 (9) - --> 2 Cr203 (aq) The substace being oxidized and the one being reduced, respectively are: O 02 (g) & Cr O Cr (s) & O2 (g) O 02 (9) & Cr203 (aq) O Cr (S) & Cr203 (aq) D 4.5 pc

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