Given a Havard architecture microprocessor with the following assembly instruction timing: \begin{tabular}{|1|1|1|} \hline Instruction & Description & Clock cycles \hline ADD & Addition & 5 MUL & Multiplication & 20 \hline \end{tabular) Which of the following code is faster? Explain. \begin{tabular}{|1|1|} \hline$/ /$ Code $A$ & $/ /$ Code $B$ $a=6$ & $a=6$ $b=0$ & $b=0$ $b=a * 5$ & $b=b+a$ $b=b+a$ & $b=b+a$ $b$ & $b=b+a$ $b=b+a$ \end{tabular CS. JG.006