Given a matrix A (as an np.array), return a vector v as an np.array with shape (3,) in a way that depends on the injective, surjective, and bijective properties of A.

If A is bijective, return a vector v such that Av = . If A is not bijective because it is not injective, return a vector v such that Av =A. If A is not bijective because it is not surjective, return a vector v where the first two coordinates of v are 1 and v=Ax for some vector x.

Note that for this problem A will always either be surjective or injective.

(a) A= np.array([[1,2,3],[2,1,1]]) # your code here v = None

(b) A= np.array([[1,2],[3,4],[10,6]]) # your code here v = None

(c) A= np.array([[1,2,3],[3,4,5],[4,10,6]]) # your code here v = None

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