Given a natural number m, prove for any natural number n > m there must exist...

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Given a natural number m, prove for any natural number n > m there must exist a unique solution to the equation m+= n. (Note: after we prove this fact we can denote this unique solution by n-m.) (Hint: this question has two parts, existence and uniqueness of a solution. For the existence part use the WOP: one needs to define a set S. that is non-empty, and the smallest element of S is actually the solution we are looking for.) Given a natural number m, prove for any natural number n > m there must exist a unique solution to the equation m+= n. (Note: after we prove this fact we can denote this unique solution by n-m.) (Hint: this question has two parts, existence and uniqueness of a solution. For the existence part use the WOP: one needs to define a set S. that is non-empty, and the smallest element of S is actually the solution we are looking for.)

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To prove that for any natural number m there exists a unique solution to the equation m x n where n ... View the full answer