Given a normal random variable X with mean $64$ and variance $25,$ and a random

sample of size $n$ taken from the distribution, what sample size $n$ is necessary in order

that $P(63\mathrm{.}8\stackrel{}{x}64\mathrm{.}2)=0\mathrm{.}95?$

Click here to view page $1$ of the standard normal distribution table.

Click here to view page $2$ of the standard normal distribution table.

The necessary sample size is $n=$

$($Round up to the nearest whole number.$)$