Given a simple circular curve with the following properties, the degree of curve D $=11\backslash$deg $,$ Direction PI

$0$ to PI $1$ is $99\backslash$deg $2725,$ PI $1$ to PI $2$ is $131\backslash$deg $1005.$ The chainage of PI $1$ is $12+690\mathrm{.}010$ and the

coordinates of PI $1$ are $(-16345\mathrm{.}425$; $+6535\mathrm{.}020)$

Determine the following:

H$.$ Chainage of BC $(2)$

I. Chainage of MP $(2)$

J$.$ Chainage of EC $(2)$