Question: Given a singly linked list contains six nodes and simply show as 6 - > 5 - > 4 - > 3 - > 2

Given a singly linked list contains six nodes and simply show as 6->5->4->3->2->1, where the head reference refers to the first node (contains 6 as its item). What is the first node (referred by head) if the following statements are applied?
Node prev = head;
Node curr = head;
while(curr!=null && curr.next!=null){
if(prev.element %2==0){
prev = curr;
curr = curr.next;
}
else{
prev = prev.next;
curr = curr.next.next;
}
}
head = prev;
Question 1 options:
A)
3
B)
4
C)
5
D)
2

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