Question: Given a sorted array of integers, what can be the minimum worst case time complexity to find ceiling of a number x in given

Given a sorted array of integers, what can be the minimum worst

Given a sorted array of integers, what can be the minimum worst case time complexity to find ceiling of a number x in given array? Ceiling of an element x is the smallest element present in array which is greater than or equal to x. Ceiling is not present if x is greater than the maximum element present in array. For example, if the given array is {12, 67, 90, 100, 300, 399} and x = 95, then output should be 100. Your answer: O O(Logn) O(Logn Logn) O(LogLogn) O O(n)

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