Question: Given: AD = CF BC = DE A B O D E Prove: AB = EF Statement Reason 1. AD = CF given 2. AD

Given: AD = CF BC = DE A B O D E Prove: AB = EF Statement Reason 1. AD = CF given 2. AD = AB + BC + CD CF = CD + DE + EF segment addition 3. AB + BC + CD = CD + DE + EF Transitive Property of Equality 4. AB + BC = DE + EF 5. BC = DE given 6. AB = EF Subtraction Property of Equality What is the reason for the fourth statement in this proof? O A. definition of collinear points O B. segment addition O C. Subtraction Property of Equality O D. Substitution Property of Equality

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