Question: Given an array of n integers, arr, make the values equal using the minimum number of operations. Either choose an element and apply the operation:

Given an array of n integers, arr, make the values equal using the minimum number of operations.
Either choose an element and apply the operation:
If the operation number is odd (e.g., first, third, fifth,), then increase the element by 1.
If the operation number is even (e.g., second, fourth, sixth,...), then increase the element by 2.
or do nothing.
Only one element can change in an operation.
Calculate the minimum number of operations required to make all elements equal.
Example
arr =[1,2,4]
Operation Operation type Resulting arr
Number
1 Choose the 1 st element [2,2,4]
and add 1 since operation
number is odd.
2 choose the 2nd element and [2,4,4]
add 2
3 skip this day [2,4,4]
4 choose the 1st element and [2,4,4]
add 1
the minimum operations required is 4
Function Description
Complete the function minimumCycles in the editor below.
minimumCycles has the following parameter:
int arr[n]: the integers to equalize
Returns
long: the minimum number of operations required to equalize the array
Constraints
1<= n<=2*10^5
1<= arr[i]<=10^9
Input Format For Custom Testing
The first line contains an integer n, the size of arr.
arr[i].
Each of the next n lines contains an integer arr[i]
# Complete the 'minimumCycles' function below.
#
# The function is expected to return a LONG_INTEGER.
# The function accepts INTEGER_ARRAY arr as parameter.
#
def minimumCycles(arr) :
# Write your code here
if __name__=='__main__':
fptr = open (os. environ ['OUTPUT_PATH'],'w')
arr_count = int(input ().strip())
arr =[]
for _ in range (arr_count) :
arr_item = int(input(). strip ())
arr. append (arr_item)
result = minimumCycles (arr)
fptr. write(str (result)+'
')
fptr. close ()

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