Question: Given an ordered list and value , the LowerBound algorithm provide the position in list such that is the first offset in of a value

Given an ordered list and value , the LowerBound algorithm provide the position in list
such that is the first offset in of a value larger-equal to . Hence, <=[](or, if no such offset exists,
=||). The LowerBound algorithm does so in \Theta (log2
(||)) comparisons.
Argue that LowerBound is worst-case optimal: any algorithm that finds the correct position for any
inputs and using only comparisons will require \Theta (log2
(||)) comparisons

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