Given an undirected graph G hV, Ei, let the TWO HOP COUNT of a vertex v be the number of unique vertices that can be reached from v (not including itself) using at most 2 edges Prove that the number of vertices in G with an odd TWO HOP COUNT is even Hint Try transforming G into a different graph G0 , in such a way that you can use the handshaking lemma on G0 3 Given an undirected graph G V,B), let the TWO HOP COUNT of a vertex v be the number of unique vertices that can be reached from v (not including itself) using at most 2 edges Prove that the number of vertices in G with an odd TWO HOP COUNT is even Hint Try transforming into a different graph G,, in such a way that you can use the handshaking lemma on G

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Question: Given an undirected graph G = hV, Ei, let the TWO-HOP-COUNT of a vertex v be the number of unique vertices that can be reached

Given an undirected graph G = hV, Ei, let the TWO-HOP-COUNT of a vertex v be the number of unique vertices that can be reached from v (not including itself) using at most 2 edges. Prove that the number of vertices in G with an odd TWO-HOP-COUNT is even. Hint: Try transforming G into a different graph G0 , in such a way that you can use the handshaking lemma on G0 . Given an undirected graph G = hV, Ei, let the TWO-HOP-COUNT of

3. Given an undirected graph G-V,B), let the TWO-HOP-COUNT of a vertex v be the number of unique vertices that can be reached from v (not including itself) using at most 2 edges. Prove that the number of vertices in G with an odd TWO-HOP-COUNT is even. Hint: Try transforming into a different graph G,, in such a way that you can use the handshaking lemma on G

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