Question: Given any triangle ABC with corresponding side lengths a, b, and c, the law of cosines states: B C A A. c' = al +

Given any triangle ABC with corresponding side lengths a, b, and c, the law of cosines states: B C A A. c' = al + 1 - 2abcos(C) B. c' = al - b - 2becos(C) C. c' = al + b - 2bc cos( B) D. c' = al + b - 2bc cos(A)

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