Given at $25C$

$C(g)+B(g)A+D(g)K_1$

$A(g)+2B(g)AB(g),K_2$

Find the equilibrium constant $K_3$ for the following reaction at $25C$

$3A(g)+2D(g)(AB)(g)+2C(g)$:$K_3=$

a$.K_{1}2K_2$

b$.(K_1{)}^{-2}{K}_2$

c$.K_1{K}_2^2$

d$.K_1{K}_2^{-2}$

e$.K_1{K}_2^{-3}$