Question: Given double x = < any positive value less than 2003 >; which of the following code fragments set int y to the smallest integer
Given double x = < any positive value less than 2003 >; which of the following code fragments set int y to the smallest integer that is NOT less than three quarters of x? I. int y = (int)(3 * x / 4); if (y < 3 * x / 4) y++; II. int y = 1; while (y < 3 * x / 4) y++; III. int y = 2010 - (int)(2010 - x * 3 / 4);
(A) I only
(B) II only
(C) I and II
(D) I and III
(E) I, II, and III
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
