Given $f(x)=\frac{x^3}{3}-\frac{x^2}{2}-2x+3$;$,[-3,3]$

Find Absolute max $\frac{?}{mi{n}^2}$ of over $-3,3$

Absmax $=$atx$=$

$\frac{\text{A}\text{b}\text{s}\text{m}\text{i}\text{n}}{\text{A}\text{n}\text{s}\text{w}\text{e}\text{r}}=at-x=$

Given $f(x)=\frac{x^3}{3}-\frac{x^2}{2}-6x+5,$ find rel max $1$ min of $f.$

Relmax$=$ at $x=$

Relmin $=$ at $x=$

Answer