Given four positive integers a, b, c, and d, compute the sum of those among them that are odd.

Hint: Because you have not yet learned how to make decisions, use the fact that for a positive integer n, the expression n % 2 is either 0 or 1. You can multiply the integer n by (n % 2) to yield either zero (for even numbers) or n (for odd).

#include

using namespace std;

int main() { int n, odd_sum; // These values will be changed during testing int a = 13; int b = 10; int c = 9; int d = 2;

for (int i = 1; i <= a; ++i){ odd_sum += i; } cout << "Odd sum: " << odd_sum;

return 0; }