Question: Given function: f(x ) = 4x3-4x2- 2x-1 * 2 + 2 x - 2 . Find the horizontal asymptotes and put as an equationTo find




Given function: f(x ) = 4x3-4x2- 2x-1 * 2 + 2 x - 2 . Find the horizontal asymptotes and put as an equationTo find oblique asymptote . - Let , f ( m ) = 4 x - 4x12 - 2 x- 1 2 2 + 2 x - 2 We can use long divison to find the quotient of (4x-4x2 2n-1) and (x2+2x-2). so 1 4x1 - 12 2 + 2 x-2 ) 42 3- 4212- 2 21-1 ( * ) 0 - 12 2 2 + 6 21 -1 - 12 x1 - 2491 +24 ( + ) ( + ) 0 + 30n - 25 From this methods, we see that f ( n ) = ( 4x-12) + 30x- 25 n p 2n - 2 so, focusing on the quotient, the oblique asymptote of + ( n) is 1 = 4 x- 12
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