Given G=(G;*) is group and HG and given set N(H) N(H) = {g EG| gHg =...

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Given G=(G;*) is group and H≤G and given set N(H) N(H) = {g EG| gHg¹ = H} Prove that HAGN(H)=G Given G=(G;*) is group and H≤G and given set N(H) N(H) = {g EG| gHg¹ = H} Prove that HAGN(H)=G

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The set NH is called the normalizer of H in G and it consists of all elements g in G t... View the full answer