Question: Given in the table are the BMI statistics for random samples of men and women. Male BMI Female BMI Assume that the two samples are

 Given in the table are the BMI statistics for random samplesof men and women. Male BMI Female BMI Assume that the twosamples are independent simple random samples selected from H1 H2 normally distributed

Given in the table are the BMI statistics for random samples of men and women. Male BMI Female BMI Assume that the two samples are independent simple random samples selected from H1 H2 normally distributed populations, and do not assume that the population standard n 48 48 deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level X 27.6298 24.5485 for both parts. S 8.433923 4.913836 . . . a. Test the claim that males and females have the same mean body mass index (BMI). What are the null and alternative hypotheses? O A. HO: H1 # H2 OB. Ho: H1 2 H2 H1: H1

H2 H1: H1 # H2 The test statistic, t, is (Round to two decimal places as needed.)Researchers conducted a study to determine whether magnets are effective in treating back pain. Pain was measured | using the visual analog scale, and the results shown below are among the results obtained in the study. Higher scores correspond to greater pain levels. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) to (c) below. Reduction in Pain Level After Magnet Treatment (p4): n=19, x=0.52,s=0.88 Reduction in Pain Level After Sham Treatment (p3): n=19, x=048,s=143 a. Use a 0.01 significance level to test the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment (similar to a placebo). What are the null and alternative hypotheses? Ho: i1 p2 Ho: g # 2 Ho: M1 =H2 Hi:pg H2 H1: H1 > H2 O C. HO: H1 S H2 O D. HO: H1 = H2 H1: H1 > H2 H1: 41 # H2 The test statistic is 1.86 . (Round to two decimal places as needed.) The P-value is 0.041 . (Round to three decimal places as needed.)

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