Given is a differential equation y x 2 y 2 y x 2 y 2 with y ( 1 ) 1 2 y(1) 1 2 Using Runge Kutta method, evaluate y ( 1 05 ) y(1 05) a 1 3236 b 1 3326 c 1 2633 d 1 6233

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Given is a differential equation y   x 2   y 2 y  x 2  y 2 with y ( 1 )   1 2 y(1) 1 2  Using Runge Kutta method, evaluate y ( 1 05 ) y(1 05)  a  1 3236 b  1 3326 c  1 2633 d  1 6233

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Question: Given is a differential equation y = x 2 + y 2 y =x 2 +y 2 with y ( 1 ) = 1.2 y(1)=1.2.

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