Given $lny=-ax+\frac{b}{x}+c,$ what is $\frac{dy}{dx}?A,b,$ and c are constants.

Select one or more:

A$.\frac{dy}{dx}=-a-\frac{b}{x^2}$

B$.\frac{dy}{dx}=-a{x}^2-\frac{b}{x^2}$

C$.\frac{dy}{dx}=-ax-\frac{b}{x}$

D$.\frac{dy}{dx}=-ax+\frac{b}{x}$