Question: Given: m || CB Prove: mABC + mBAC + mACB = 180 A triangle and line are shown. Line m contains points X and Y.

Given: m || CB Prove: mABC + mBAC + mACB = 180 A triangle and line are shown. Line m contains points X and Y. Triangle A B C sits on line M at point A. Line m and line segment B C are parallel. Which statement justifies that angle XAB is congruent to angle ABC? Corresponding angles of parallel lines cut by a transversal are congruent. Vertical angles are congruent. Same-side interior angles of parallel lines cut by a transversal are supplementary. Alternate interior angles of parallel

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