Question: Given: mean= (2+2+3+4+0)/5 = 2.2 Uncertainty is 0.66 How do you calculate the distinguishability value using only the mean and uncertainty? (Use the One-Sample distinguishability

Given:

mean= (2+2+3+4+0)/5 = 2.2

Uncertainty is 0.66

How do you calculate the distinguishability value using only the mean and uncertainty? (Use the One-Sample distinguishability test).

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