Question: Given p(Y, u) show that exp(-u)(u) and p(u) = y! Y, u~ Poisson -1 exp(-ku), that is which implies Y~NB(k, ). (pu), u~ Gamma(k,

Given p(Y, u) show that exp(-u)(u)" and p(u) = y! Y, u~ Poisson -1 exp(-ku), that is which implies Y~NB(k, ). (pu), u~ Gamma(k, =), I(y k) p(3. k. 4) =(K)+41 (4)*(1-)". p(y; T(k)(y k y = 0, 1, 2,...,
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Given that pYu u exppu puYu Yu and pu expku kuk1 uk1 eu we can derive the probability mas... View full answer
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