Given S for propane gas at $273\mathrm{.}15$ K and $4\mathrm{.}504$ bar is $60\mathrm{.}0$ J$/$mol$$K$.$ Calculate S for propane

gas at $554\mathrm{.}7$ K and $21\mathrm{.}24$ bar using the generalized second$-$virial$-$coefficient correlations $($R$$ICPS is given

as $62\mathrm{.}2$ J$/$mol$$K for this process$).$

$($a$)49\mathrm{.}3$ J$/$mol$$K $($b$)110\mathrm{.}1$ J$/$mol$$K $($c$)123\mathrm{.}0$ J$/$mol$$K $($d$)142\mathrm{.}5$ J$/$mol$$K