Question: Given steps 1-4, determine the H r for net reaction below. Step 1: B 2 O 3 (s) + 3 H 2 O (g) 3
Given steps 1-4, determine the Hr for net reaction below.
Step 1: B2O3(s) + 3 H2O(g) 3 O2(g) + B2H6(g) |||||||||| Hr = 2035 kJ/mol
Step 2: H2O(l) H2O(g) |||||||||||||||||||||||||||||||||||||||||||||||||| Hr = 44.0 kJ/mol
Step 3: 2 H2(g) + O2(g) 2 H2O(l) ||||||||||||||||||||||||||||||||| Hr = -572 kJ/mol
Step 4: 2 B(s) + 3 H2(g) B2H6(g) |||||||||||||||||||||||||||||||||| Hr = 36 kJ/mol Net Reaction: 4 B(s) + 3 O2(g) 2 B2O3(s)
NOTE: (I used the "||||||" to space the data to the side, it does not represent numerical information whatsoever.) I would like some guidance on how to do this step-by-step! Tips are 100% appreciated. Thank you so much.
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