Given that ${\displaystyle \underset{0}{\overset{b}{}}}xdx=\frac{b^2-a^2}{2},$ use this result and the fact that ${\displaystyle \underset{0}{\overset{\frac{}{2}}{}}}cos(x)dx=1,$ together with the properties of definite integrals, to evaluate ${\displaystyle \underset{0}{\overset{\frac{}{2}}{}}}(3cos(x)-4x)dx.$SCalc$94\mathrm{.}209$

Given that ${\displaystyle \underset{0}{\overset{b}{}}}xdx=\frac{b^2-a^2}{2},$ use this result and the fact that ${\displaystyle \underset{0}{\overset{\frac{}{2}}{}}}cos(x)dx=1,$ together with the properties of definite integrals, to evaluate ${\displaystyle \underset{0}{\overset{\frac{}{2}}{}}}(3cos(x)-4x)dx.$

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