Question: Given that CaO(s) + H2O(l) --> Ca(OH)2(s), delta Hrxn = -64.8 kJ/mol, how many grams of CaO must react in order to liberate 525 kJ

Given that CaO(s) + H2O(l) --> Ca(OH)2(s), delta Hrxn = -64.8 kJ/mol, how many grams of CaO must react in order to liberate 525 kJ of heat?

 

 

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