Question: Given that f (2) = 2202 - 42 + 3 what is the absolute maximum value of f(x) on the interval [0, 2]

Given that f (2) = 2202 - 42 + 3 what
is the absolute maximum value of f(x) on the interval [0, 2]

Given that f (2) = 2202 - 42 + 3 what is the absolute maximum value of f(x) on the interval [0, 2]

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