Given that:

int$[]$ list $=\{2,7,14,18,23,27,32,38,42,48,53,57,61,68,73\}$;

and:

int targetValue $=4$;

and given this Binary Search algorithm:

public static int BinarySearch$($int$[]$ list, int targetValue$)\{$

int mid, low, high;

low $=0$;

high $=$ list.length $-1$;

while $($high $>=$ low$)\{$

mid $=($high $+$ low$)/2$;

if $($list$[$mid$]<$ targetValue$)\{$

low $=$ mid $+1$;

$\}$ else if $($list$[$mid$]>$ targetValue$)\{$

high $=$ mid $-1$;

$\}$ else $\{$

return mid;

$\}$

$\}$

return $-1$; $//$ not found

$\}$

Which value in list will be the third to be compared to the targetValue in a binary search for the target value?

public void accelerate$($int increment$)\{$

this.speed $+=$ increment;

$\}$

public void brake$($int decrement$)\{$

this.speed $-=$ decrement;

$\}$

$\}$

$...$

Bike b$1=$ new Bike$(34),$ b$2=$ new Bike$(41)$;

b$1=$ b$2$;

b$2.$accelerate$(8)$;

b$2.$brake$(5)$;

System.out.println$($b$1.$speed$)$;