Given that JMMK , identify a two-column proof that proves JL>KL . The figure shows two triangles M J L and M K L. Side M L is a common side for both triangles. Side J M is congruent to side M K in the other triangle. The angle L M J contains angles J M K and K M L. 1.JMMK (Given)2.MLML (Reflex. Prop. of )3.mLMK=mJMK mJML ( Add. Post.)4.mLMJ>mKML (Given)5. JL>KL (Hinge Thm.) 1.JMMK (Given)2.MLML (Symm. Prop. of )3.mLMJ=mJMK mKML ( Add. Post.)4.mLMJ>mKML (Comparison Prop. of Inequal.)5. JL>KL (Hinge Thm.) 1.JMMK (Given)2.MLML (Conv. of Hinge Thm.)3.mLMJ=mJMK mKML ( Add. Post.)4.mLMJ>mKML (Comparison Prop. of Inequal.)5. JL>KL (Reflex. Prop. of ) 1.JMMK (Given)2.MLML (Reflex. Prop. of )3.mLMJ=mJMK mKML ( Add. Post.)4.mLMJ>mKML (Comparison Prop. of Inequal.)5. JL>KL (Hinge Thm.)