Question: Given that K b for NH 2 NH 2 = 1.7 x 10 -6 and Kw =1.0 x 10 -14 at 25C, calculate the equilibrium

Given that Kb for NH2NH2 = 1.7 x 10-6 and Kw =1.0 x 10-14 at 25⁰C, calculate the

equilibrium constant for the reaction at 25⁰C.

NH2NH3+(aq) + H2O(l) ⇌ NH2NH2(aq) + H3O+(aq)

5.9 x 105

5.9 x 109

1.7 x108

5.9 x 10-9

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