Question: Given that ko for Oxygen is 0.5, ko for Boron is 0.8 and ko for Gold is 2.5 x 10^-5. Essentially, the code in matlab

 Given that ko for Oxygen is 0.5, ko for Boron is

Given that ko for Oxygen is 0.5, ko for Boron is 0.8 and ko for Gold is 2.5 x 10^-5. Essentially, the code in matlab to plot k0(1-f)^ko-1 vs f is needed for any values of f.

(2) Using formula calculate and plot (in the same figure) CsCo vs. f for oxygen (O), Boron (B) and gold (Au). Include code and plot printouts. If we want to get rid of the gold contamination, which part of the pulled ingot we need to discard and why

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