Question: Given that rectangle ABCD has coordinates A(0,0) , B(12,0) , C(12,6) , and D(0,6) , F is the midpoint of AB , and G is

Given that rectangle ABCD has coordinates A(0,0) , B(12,0) , C(12,6) , and D(0,6) , F is the midpoint of AB , and G is the midpoint of CD , which of the following proves that FB=GC ? By the Midpoint Formula, the coordinates of F are (6, 0) and the coordinates of G are (6, 6). Then FB = 6, and GC = 6. Thus FB = GC. By the Distance Formula, the coordinates of F are (6, 12) and the coordinates of G are (6, 0). Then FG = 6, and GC = 6. Thus FG = GC. By the Distance Formula, the coordinates of F are (6, 0) and the coordinates of G are (6, 6). Then FB = 12, and GC = 12. Thus FB = GC. By the Midpoint Formula, the coordinates of F are (6, 6) and the coordinates of G are (6, 0). Then FB = 6, and GC = 6. Thus FB = GC

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