Given that the acceleration vector $isa(t)=(-(cos(t)))i+(-(sin(t)))j+(-5t)k,$ the initial velocity $isv(0)=i+k,$ and the initial position vector $isr(0)=i+j+k,$ compute:

$A.$ The velocity vector $v(t)=$

$i+$

$j+$

$k$

$B.$ The position vector $r(t)=$

$i+$

$j+$

$k$