Question: Given that the acceleration vector is a(t) = (-4 cos(2t))i + (-4 sin(2t))j+(-2t)k, the initial velocity is v(0) = i +k, and the initial


Given that the acceleration vector is a(t) = (-4 cos(2t))i + (-4

Given that the acceleration vector is a(t) = (-4 cos(2t))i + (-4 sin(2t))j+(-2t)k, the initial velocity is v(0) = i +k, and the initial position vector is r(0) i+j+k, compute: A. The velocity vector v(t) = i+ 5+ 0 k B. The position vector r(t) = it 5+ k Note: You can earn partial credit on this problem. point) Consider the helix r(t) = (cos(8t), sin(8t), -4t). Compute, at t A. The unit tangent vector T = (0,0,0) B. The unit normal vector N C. The unit binormal vector B DO H

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