Question: Given the differential equation y + 2y + 5y = -50 sin 5t find a solution of the form y= A cos 5t +


Given the differential equation y" + 2y + 5y = -50 sin 5t find a solution of the form y= A cos 5t + B sin 5t. Solve the initial value problem. y" + 2y + y = 0, y(0) = 1, y'(0) = -3
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