Question: Given the equation AV=AV e RC with Io the initial current, I the voltage at a moment t (both in amperes) AVc the voltage on

Given the equation

Given the equation AV=AV e RC with Io the initial current, Ithe voltage at a moment t (both in amperes) AVc the voltageon the capacitor at a moment t AVo is the initial voltage(both in volts), time t (in seconds), R is the resistance (in

AV=AV e RC with Io the initial current, I the voltage at a moment t (both in amperes) AVc the voltage on the capacitor at a moment t AVo is the initial voltage (both in volts), time t (in seconds), R is the resistance (in ohms), and C is the capacitance. Fig 3 . If you take the logarithm of the voltage formula, you get a linear relationship between InA Vc and t: In AV=InAV. -7 t RC T=RC is defined as the time constant: a characteristic time for a circuit. A long time constant implies a slow discharge; a short time constant, a rapid discharge. The slope of the line representing the graph InA Vc vs t is the opposite of the inverse of the time constant. In AV=InAV, -, slope = =1\f\fCapacitance (F) 474 uIF=0.000474 F Theoretical time constant 1 micro farad (HF) = 10^-6 farads (F) Larger resistance R, (kn) 163 kn v= 163 000 0 Tuh = RC(9) (163000 0)(0.000474 F )= 77.262 seconds I is the time constant in s R. is the resistance in C is the in F Smaller resistance R, (kn) 48 kn=48000 0 Tah = RC (9) (48000 0)(0.000474 F)=22.752 seconds Voltage supply = (V) 8.00 V

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