Question: Given the equations below f zz = 6 z x y e z f x = yz + 2 x ycos ( x y )

Given the equations below

fzz=6zxyez

fx=yz+2xycos(xy)yez

fzy=xxez

fy=xzxcos(xy)xez

fzx=yyez

and

fz(1,,0)=0

f(1,,0)=1

How can I find all functions of f(x,y,z)

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